[Pw_forum] Trying to clarify the dipole correction (again!)
Stefano de Gironcoli
degironc at sissa.it
Thu Aug 13 17:59:14 CEST 2009
Dear J.J. Ramsey
at variance with what is defined in Bengtsson's paper the dipole
potential is not discontinuous in QE but is defined by periodically
alternating an increasing slope (associate to the "physical" electric
field present in the cell) and a rapidly decreasing slope that should
be located in a region of negligibly small charge density. This is done
to avoid too sharp features in the calculation. The definition is also
generalized so that the region where the dipole correction operates can
be centered in an arbitrary point of the cell and not just in the center
of it as defined in the paper.
the regression region (the region with a rapidly decreasing slope)
occupies a fraction eopreg of the cell size while the maximum of the
increasing slope occurs at a fraction emaxpos.
so if emaxpos = 0.45 and eopreg=0.1 the region where the correction
is physically meaningful goes from -45% to +45% of the cell and the
regression region (that should contains no charge density) occupies
the central 10% of the cell. This is a good setting if you center your
slab around the origin.
if instead emaxpos=0.95 and eopreg=0.1 the the dipole correction is
applied for +5% to +95% of the cell while in the rest one have the
regression region. this is OK if you put your slab in the center of the
cell.
Stefano de Gironcoli - SISSA and DEMOCRITOS
J. J. Ramsey wrote:
> In the reference on the dipole correction used in QE, L. Bengtsson, PRB 59, 12301 (1999), the dipole potential is given as
>
> V_dip(z) = 4*pi*m*(z/z_m - 0.5), 0 < z < z_m
>
> where z_m is the height of the box, and there is a discontinuity in the potential at z = 0,z_m. I'm not sure how this fits into the QE documentation on the dipole correction. Is V_dip in QE supposed to be something like this?:
>
> V_dip(z) = 4*pi*m*[z/z_m - (emaxpos + eopreg -1)], emaxpos + eopreg -1 < z/z_m < emaxpos;
> = something with a steep but finite slope, otherwise
>
> My guess is probably wrong, but the explanations in the documentation of the roles of emaxpos and eopreg appear to be tied to the case where eamp is nonzero. I'm not sure if the documentation for the dipfield variable is supposed to indicate that the actual slope of the potential is supposed to be eamp + 4*pi*m/z_m.
>
> University of Akron
> Civil Engineering (!) Dept.
>
>
>
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