[Pw_forum] q2r.x error

[Li yan-ling]

Dear all users,
  Thanks the answer. Now I want to know which program results in the
output data possessing the stars (**) in "a2Fq2r.5*" file. What is the
nature of this case?
  I checked the input file, I think it's right. The input files is as
follows.
---------------------------------
### scf.fit.in ###

 &control
    calculation='scf'
    restart_mode='from_scratch'
    pseudo_dir = '../',
    outdir='./tmp/'
    prefix='ren'
 /
 &system
    ibrav= 4, a = 2.7435, c = 5.7985,nat= 4, ntyp= 2,nbnd =32,
    ecutwfc =32.0, ecutrho = 400.0,
occupations='smearing',smearing='methfessel-paxton',
    degauss=0.03,la2F=.true.,
 /
 &electrons
    conv_thr = 1.0d-10
    mixing_beta = 0.5
 /
ATOMIC_SPECIES
 Re  186.207 Re.pw91-n-van.UPF
 N   14.0067 N.pw91-van_ak.UPF
ATOMIC_POSITIONS crystal
 Re 0.00  0.00  0.00
 Re 0.00  0.00  0.50
 N  0.333333333 0.666666666 0.25
 N  0.666666666 0.333333333 0.75
K_POINTS {automatic}
 36 36 16 0 0 0

###scf.in####
 &control
    calculation='scf'
    restart_mode='from_scratch'
    pseudo_dir = '../',
    outdir='./tmp/'
    prefix='ren'
 /
 &system
    ibrav= 4, a = 2.7435, c = 5.7985,nat= 4, ntyp= 2,nbnd=32,
    ecutwfc =32.0,ecutrho = 400.0,
occupations='smearing',smearing='methfessel-paxton',
    degauss=0.03,
 /
 &electrons
    conv_thr = 1.0d-10
    mixing_beta = 0.5
 /
ATOMIC_SPECIES
 Re 186.207 Re.pw91-n-van.UPF
 N  14.0067 N.pw91-van_ak.UPF
ATOMIC_POSITIONS crystal
 Re 0.00  0.00  0.00
 Re 0.00  0.00  0.50
 N  0.333333333  0.666666666  0.25
 N  0.666666666  0.333333333  0.75
K_POINTS {automatic}
 16 16 8 0 0 0

####ph.in####
Electron-phonon coefficients for ReN
&inputph
tr2_ph=1.0d-13,
prefix='ren',
fildvscf='rendv',
amass(1)=186.207,amass(2)=14.0067,
outdir='./tmp/',
fildyn='ren.dyn',
elph=.true.,
trans=.true.,
ldisp=.true.
nq1=4,nq2=4,nq3=2
/

#####q2r.in####
 &input
zasr='simple',
fildyn='ren.dyn',
flfrc='ren442.fc',
la2F=.true.
/
---------------------------------------------
  The system studied have the NiAs symmetry with the P63/mmc spacegroup.
If you can tell me the answer, it's my pleasure.

  Thanks in advance.

Yanling Li.